Optimal. Leaf size=98 \[ \frac {i a \sec ^7(c+d x)}{7 d}+\frac {5 a \tanh ^{-1}(\sin (c+d x))}{16 d}+\frac {a \tan (c+d x) \sec ^5(c+d x)}{6 d}+\frac {5 a \tan (c+d x) \sec ^3(c+d x)}{24 d}+\frac {5 a \tan (c+d x) \sec (c+d x)}{16 d} \]
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Rubi [A] time = 0.06, antiderivative size = 98, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 3, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {3486, 3768, 3770} \[ \frac {i a \sec ^7(c+d x)}{7 d}+\frac {5 a \tanh ^{-1}(\sin (c+d x))}{16 d}+\frac {a \tan (c+d x) \sec ^5(c+d x)}{6 d}+\frac {5 a \tan (c+d x) \sec ^3(c+d x)}{24 d}+\frac {5 a \tan (c+d x) \sec (c+d x)}{16 d} \]
Antiderivative was successfully verified.
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Rule 3486
Rule 3768
Rule 3770
Rubi steps
\begin {align*} \int \sec ^7(c+d x) (a+i a \tan (c+d x)) \, dx &=\frac {i a \sec ^7(c+d x)}{7 d}+a \int \sec ^7(c+d x) \, dx\\ &=\frac {i a \sec ^7(c+d x)}{7 d}+\frac {a \sec ^5(c+d x) \tan (c+d x)}{6 d}+\frac {1}{6} (5 a) \int \sec ^5(c+d x) \, dx\\ &=\frac {i a \sec ^7(c+d x)}{7 d}+\frac {5 a \sec ^3(c+d x) \tan (c+d x)}{24 d}+\frac {a \sec ^5(c+d x) \tan (c+d x)}{6 d}+\frac {1}{8} (5 a) \int \sec ^3(c+d x) \, dx\\ &=\frac {i a \sec ^7(c+d x)}{7 d}+\frac {5 a \sec (c+d x) \tan (c+d x)}{16 d}+\frac {5 a \sec ^3(c+d x) \tan (c+d x)}{24 d}+\frac {a \sec ^5(c+d x) \tan (c+d x)}{6 d}+\frac {1}{16} (5 a) \int \sec (c+d x) \, dx\\ &=\frac {5 a \tanh ^{-1}(\sin (c+d x))}{16 d}+\frac {i a \sec ^7(c+d x)}{7 d}+\frac {5 a \sec (c+d x) \tan (c+d x)}{16 d}+\frac {5 a \sec ^3(c+d x) \tan (c+d x)}{24 d}+\frac {a \sec ^5(c+d x) \tan (c+d x)}{6 d}\\ \end {align*}
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Mathematica [A] time = 0.31, size = 61, normalized size = 0.62 \[ \frac {a \left (3360 \tanh ^{-1}(\sin (c+d x))+(1981 \sin (2 (c+d x))+700 \sin (4 (c+d x))+105 \sin (6 (c+d x))+1536 i) \sec ^7(c+d x)\right )}{10752 d} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.54, size = 372, normalized size = 3.80 \[ \frac {-210 i \, a e^{\left (13 i \, d x + 13 i \, c\right )} - 1400 i \, a e^{\left (11 i \, d x + 11 i \, c\right )} - 3962 i \, a e^{\left (9 i \, d x + 9 i \, c\right )} + 6144 i \, a e^{\left (7 i \, d x + 7 i \, c\right )} + 3962 i \, a e^{\left (5 i \, d x + 5 i \, c\right )} + 1400 i \, a e^{\left (3 i \, d x + 3 i \, c\right )} + 210 i \, a e^{\left (i \, d x + i \, c\right )} + 105 \, {\left (a e^{\left (14 i \, d x + 14 i \, c\right )} + 7 \, a e^{\left (12 i \, d x + 12 i \, c\right )} + 21 \, a e^{\left (10 i \, d x + 10 i \, c\right )} + 35 \, a e^{\left (8 i \, d x + 8 i \, c\right )} + 35 \, a e^{\left (6 i \, d x + 6 i \, c\right )} + 21 \, a e^{\left (4 i \, d x + 4 i \, c\right )} + 7 \, a e^{\left (2 i \, d x + 2 i \, c\right )} + a\right )} \log \left (e^{\left (i \, d x + i \, c\right )} + i\right ) - 105 \, {\left (a e^{\left (14 i \, d x + 14 i \, c\right )} + 7 \, a e^{\left (12 i \, d x + 12 i \, c\right )} + 21 \, a e^{\left (10 i \, d x + 10 i \, c\right )} + 35 \, a e^{\left (8 i \, d x + 8 i \, c\right )} + 35 \, a e^{\left (6 i \, d x + 6 i \, c\right )} + 21 \, a e^{\left (4 i \, d x + 4 i \, c\right )} + 7 \, a e^{\left (2 i \, d x + 2 i \, c\right )} + a\right )} \log \left (e^{\left (i \, d x + i \, c\right )} - i\right )}{336 \, {\left (d e^{\left (14 i \, d x + 14 i \, c\right )} + 7 \, d e^{\left (12 i \, d x + 12 i \, c\right )} + 21 \, d e^{\left (10 i \, d x + 10 i \, c\right )} + 35 \, d e^{\left (8 i \, d x + 8 i \, c\right )} + 35 \, d e^{\left (6 i \, d x + 6 i \, c\right )} + 21 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 7 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 2.25, size = 181, normalized size = 1.85 \[ \frac {105 \, a \log \left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right ) - 105 \, a \log \left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1\right ) + \frac {2 \, {\left (231 \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{13} - 336 i \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{12} - 196 \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} + 595 \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 1680 i \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{8} - 595 \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 1008 i \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 196 \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 231 \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 48 i \, a\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{7}}}{336 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.45, size = 95, normalized size = 0.97 \[ \frac {i a}{7 d \cos \left (d x +c \right )^{7}}+\frac {a \left (\sec ^{5}\left (d x +c \right )\right ) \tan \left (d x +c \right )}{6 d}+\frac {5 a \left (\sec ^{3}\left (d x +c \right )\right ) \tan \left (d x +c \right )}{24 d}+\frac {5 a \sec \left (d x +c \right ) \tan \left (d x +c \right )}{16 d}+\frac {5 a \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16 d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.35, size = 106, normalized size = 1.08 \[ -\frac {7 \, a {\left (\frac {2 \, {\left (15 \, \sin \left (d x + c\right )^{5} - 40 \, \sin \left (d x + c\right )^{3} + 33 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{6} - 3 \, \sin \left (d x + c\right )^{4} + 3 \, \sin \left (d x + c\right )^{2} - 1} - 15 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 15 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - \frac {96 i \, a}{\cos \left (d x + c\right )^{7}}}{672 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 7.37, size = 247, normalized size = 2.52 \[ \frac {5\,a\,\mathrm {atanh}\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{8\,d}-\frac {-\frac {11\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{13}}{8}+2{}\mathrm {i}\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}+\frac {7\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}}{6}-\frac {85\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9}{24}+10{}\mathrm {i}\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8+\frac {85\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5}{24}+6{}\mathrm {i}\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4-\frac {7\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{6}+\frac {11\,a\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{8}+\frac {a\,2{}\mathrm {i}}{7}}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{14}-7\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}+21\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}-35\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8+35\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6-21\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+7\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2-1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ i a \left (\int \left (- i \sec ^{7}{\left (c + d x \right )}\right )\, dx + \int \tan {\left (c + d x \right )} \sec ^{7}{\left (c + d x \right )}\, dx\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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